A) 13.6 eV
B) $ 13.6\times 11\ eV $
C) $ \frac{13.6}{11}eV $
D) $ 13.6\times {{(11)}^{2}}eV $
Correct Answer: D
(Eion)Na $ =Z^{2}{{(E_{ion})}_{H}}={{(11)}^{2}}13.6\ eV $
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