SATHEE: Atoms And Nuclei Question 214

Atoms And Nuclei Question 214

Question: If 200 MeV energy is released in the fission of a single $U^{235}$ nucleus, the number of fissions required per second to produce 1 kilowatt power shall be (Given $1 e V = 1.6 \times 10^{- 19} J$ ) [AMU 1995; MP PMT 1999]

Options:

A) $3.125 \times 10^{13}$

B) $3.125 \times 10^{14}$

C) $3.125 \times 10^{15}$

D) $3.125 \times 10^{16}$

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Answer:

Correct Answer: A

Solution:

$P = n, (\frac{E}{t}) \Rightarrow 1000 = \frac{n \times 200 \times 10^{6} \times 1.6 \times 10^{- 19}}{t}$
$\Rightarrow \frac{n}{t} = 3.125 \times 10^{13} .$

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Atoms And Nuclei Question 214

Question: If 200 MeV energy is released in the fission of a single $U^{235}$ nucleus, the number of fissions required per second to produce 1 kilowatt power shall be (Given $1 e V = 1.6 \times 10^{- 19} J$ ) [AMU 1995; MP PMT 1999]

Options:

Answer:

Solution:

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सदस्यता

एनसीईआरटी व्यायाम वीडियो समाधान

Atoms And Nuclei Question 214

Question: If 200 MeV energy is released in the fission of a single U235 nucleus, the number of fissions required per second to produce 1 kilowatt power shall be (Given 1 eV=1.6×10−19J ) [AMU 1995; MP PMT 1999]

Options:

Answer:

Solution:

इंजीनियरिंग की तैयारी

चिकित्सा तैयारी

एनसीईआरटी पुस्तकें और समाधान

महत्वपूर्ण संसाधन

अन्य संसाधन

पाठ्यक्रम

परीक्षा मंच

नमूना मॉक टेस्ट

सदस्यता

एनसीईआरटी व्यायाम वीडियो समाधान

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Question: If 200 MeV energy is released in the fission of a single $U^{235}$ nucleus, the number of fissions required per second to produce 1 kilowatt power shall be (Given $1 e V = 1.6 \times 10^{- 19} J$ ) [AMU 1995; MP PMT 1999]