Atoms And Nuclei Question 143
Question: The energy of electron in the nth orbit of hydrogen atom is expressed as $ E_{n}=\frac{-13.6}{n^{2}}eV $ . The shortest and longest wavelength of Lyman series will be [Pb. PET 2003]
Options:
A) 910 Å, 1213 Å
B) 5463 Å, 7858 Å
C) 1315 Å, 1530 Å
D) None of these
Show Answer
Answer:
Correct Answer: A
Solution:
$ \frac{1}{{\lambda_{\max }}}=R,[ \frac{1}{{{(1)}^{2}}}-\frac{1}{{{(2)}^{2}}} ] $
Þ $ {\lambda_{\max }}=\frac{4}{3R}\approx 1213,{\AA} $ and $ \frac{1}{{\lambda_{\min }}}=R,[ \frac{1}{{{(1)}^{2}}}-\frac{1}{\infty } ] $
Þ $ {\lambda_{\min }}=\frac{1}{R}\approx 910,{\AA} $
