Atoms And Nuclei Question 103

Question: Orbital acceleration of electron is [RPET 2001]

Options:

A) $ \frac{n^{2}h^{2}}{4{{\pi }^{2}}m^{2}r^{3}} $

B) $ \frac{n^{2}h^{2}}{2n^{2}r^{3}} $

C) $ \frac{4n^{2}h^{2}}{{{\pi }^{2}}m^{2}r^{3}} $

D) $ \frac{4n^{2}h^{2}}{4{{\pi }^{2}}m^{2}r^{3}} $

Show Answer

Answer:

Correct Answer: A

Solution:

$ mvr=\frac{nh}{2\pi } $
Þ $ v=\frac{nh}{2\pi mr} $
Þ $ \frac{v^{2}}{r}=\frac{n^{2}h^{2}}{4{{\pi }^{2}}m^{2}r^{3}} $ .



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