SATHEE: Some Basic Concepts Of Chemistry Question 84

Some Basic Concepts Of Chemistry Question 84

Question: Sulfuryl chloride $(S O_{2} C l_{2})$ reacts with water to give a mixture of $H_{2} S O_{4}$ and HCl. How many moles of baryta would be required to neutralize the solution formed by adding 4 mole of $S O_{2} C l_{2}$ to excess of water?

Options:

A) 1

B) 2

C) 3

D) 4

Show Answer

Answer:

Correct Answer: B

Solution:

[b] $S O_{2} C l + 2 H_{2} O \to H_{2} S O_{4} + 2 H C l$ $H_{2} S O_{4} + B a {(O H)}_{2} \to B a S O_{4} + 2 H_{2} O$ $2 H C l + B a {(O H)}_{2} \to B a C l_{2} + 2 H_{2} O$ Total moles of $B a {(O H)}_{2}$ required = 2

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Some Basic Concepts Of Chemistry Question 84

Question: Sulfuryl chloride (SO2Cl2) reacts with water to give a mixture of H2SO4 and HCl. How many moles of baryta would be required to neutralize the solution formed by adding 4 mole of SO2Cl2 to excess of water?

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Question: Sulfuryl chloride $(S O_{2} C l_{2})$ reacts with water to give a mixture of $H_{2} S O_{4}$ and HCl. How many moles of baryta would be required to neutralize the solution formed by adding 4 mole of $S O_{2} C l_{2}$ to excess of water?