Some Basic Concepts Of Chemistry Question 83
Question: The mass of $ BaCO _3 $ produced when excess $ CO _2 $ is bubbled through a solution of 0.205 mol $ Ba{{( OH )}_2} $ is:
Options:
A) 81 g
B) 40.5 g
C) 20.25 g
D) 162 g
Show Answer
Answer:
Correct Answer: B
Solution:
[b] $ \underset{1,mol}{\mathop{Ba{{( OH )}_2}}},+CO _2\xrightarrow{{}}\underset{1,mol}{\mathop{BaCO _3}},+H _2O $
$ 1,mol,Ba{{(OH)}_2}=1mol,BaCO _3 $
$ \therefore 0.205molBa{{( OH )}_2}=0.205molBaCO _3 $ Wt. of substance = No. of moles x Molecular Mass $ =0.205\times 197.3=40.5g $