SATHEE: Some Basic Concepts Of Chemistry Question 71

Some Basic Concepts Of Chemistry Question 71

Question: 1.575 g of oxalic acid ${(C O O H)}_{2} . x H_{2} O$ are dissolved in water and the volume made up to 250 mL. On titration 16.68 mL of this solution requires 25 mL of N/15 NaOH solution for complete neutralization, calculate x.

Options:

A) 3

B) 2

C) 4

D) 5

Show Answer

Answer:

Correct Answer: B

Solution:

[b] Meq of oxalic acid in 16.68 ml = Meq of NaOH $= 25 \times \frac{1}{25}$ Meq of oxalic acid in 250 ml $= 25 \times \frac{1}{15} \times \frac{250}{16.68} = 24.98$ $\frac{1.575}{(90 + 18 x) / 2} \times 1000 = 24.98$
$∴ x = 2$

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Some Basic Concepts Of Chemistry Question 71

Question: 1.575 g of oxalic acid (COOH)2.xH2O are dissolved in water and the volume made up to 250 mL. On titration 16.68 mL of this solution requires 25 mL of N/15 NaOH solution for complete neutralization, calculate x.

Options:

Answer:

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Question: 1.575 g of oxalic acid ${(C O O H)}_{2} . x H_{2} O$ are dissolved in water and the volume made up to 250 mL. On titration 16.68 mL of this solution requires 25 mL of N/15 NaOH solution for complete neutralization, calculate x.