Some Basic Concepts Of Chemistry Question 67

Question: 2.0 g of a sample contains mixture of $ SiO _2 $ and $ Fe _2{O_3} $ . On very strong heating, it leaves a residue weighing 1.96 g. The reaction responsible for loss of mass is given below.

$ Fe _2O _3(s)\to Fe _3O _4(s)+O(g), $ (unbalance equation) What is the percentage by mass of $ SiO _2 $ in original sample?

Options:

A) 100%

B) 20%

C) 40%

D) 60%

Show Answer

Answer:

Correct Answer: C

Solution:

[c] $ 3Fe _2O _3(s)\ to 2Fe _3O _4+\frac{1}{2}O _2 $ 480 g $ Fe _2O _3 $ provide $ 16g,O _2 $ . For loss of $ 0.04gO _2\ to 0.04\times \frac{480}{16}=1.2g,Fe _2O _3 $ % by mass of $ SiO _2=\frac{0.8}{2.0}\times 100=40% $ %



जेईई के लिए मॉक टेस्ट

एनसीईआरटी अध्याय वीडियो समाधान

दोहरा फलक