Some Basic Concepts Of Chemistry Question 67

Question: 2.0 g of a sample contains mixture of SiO2 and Fe2O3 . On very strong heating, it leaves a residue weighing 1.96 g. The reaction responsible for loss of mass is given below.

Fe2O3(s)Fe3O4(s)+O(g), (unbalance equation) What is the percentage by mass of SiO2 in original sample?

Options:

A) 100%

B) 20%

C) 40%

D) 60%

Show Answer

Answer:

Correct Answer: C

Solution:

[c] 3Fe2O3(s) to2Fe3O4+12O2 480 g Fe2O3 provide 16g,O2 . For loss of 0.04gO2 to0.04×48016=1.2g,Fe2O3 % by mass of SiO2=0.82.0×100=40 %



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