SATHEE: Some Basic Concepts Of Chemistry Question 43

Some Basic Concepts Of Chemistry Question 43

Question: The mass of $N_{2} F_{4}$ produced by the reaction of 2.0 g of $N H_{3}$ and 8.0 g of $F_{2}$ is 3.56 g. What is the per cent yield?

$2 N H_{3} + 5 F_{2} \to N_{2} F_{4} + 6 H F$

Options:

A) 79.0

B) 71.2

C) 84.6

D) None of these

Show Answer

Answer:

Correct Answer: D

Solution:

[d] $2 N H_{3} + 5 F_{2} \overset{}{\to} N_{2} F_{^{4}} + 6 H F$ $2 \times 17 g, N H_{3}$ gives 66 g $N_{2} F_{4}$ 2 g will give $- \frac{66}{34} \times 2 = 3.88 g, N_{2} F_{4}$ % yield $= \frac{3.56}{3.88} \times 100 = 91.75$

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Some Basic Concepts Of Chemistry Question 43

Question: The mass of $N_{2} F_{4}$ produced by the reaction of 2.0 g of $N H_{3}$ and 8.0 g of $F_{2}$ is 3.56 g. What is the per cent yield?

Options:

Answer:

Solution:

इंजीनियरिंग की तैयारी

चिकित्सा तैयारी

एनसीईआरटी पुस्तकें और समाधान

महत्वपूर्ण संसाधन

अन्य संसाधन

पाठ्यक्रम

परीक्षा मंच

नमूना मॉक टेस्ट

सदस्यता

एनसीईआरटी व्यायाम वीडियो समाधान

Some Basic Concepts Of Chemistry Question 43

Question: The mass of N2F4 produced by the reaction of 2.0 g of NH3 and 8.0 g of F2 is 3.56 g. What is the per cent yield?

Options:

Answer:

Solution:

इंजीनियरिंग की तैयारी

चिकित्सा तैयारी

एनसीईआरटी पुस्तकें और समाधान

महत्वपूर्ण संसाधन

अन्य संसाधन

पाठ्यक्रम

परीक्षा मंच

नमूना मॉक टेस्ट

सदस्यता

एनसीईआरटी व्यायाम वीडियो समाधान

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Question: The mass of $N_{2} F_{4}$ produced by the reaction of 2.0 g of $N H_{3}$ and 8.0 g of $F_{2}$ is 3.56 g. What is the per cent yield?