Some Basic Concepts Of Chemistry Question 33
Question: The density of 3M solution of sodium chloride is $ 1.252gm{L^{-1}} $ . The molality of the solution will be (molar mass, $ NaCl=585gmo{l^{-1}} $ )
Options:
A) 2.60 m
B) 2.18 m
C) 2.79 m
D) 3.00 m
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Answer:
Correct Answer: C
Solution:
[c] The relation between molarity (M) and molality (m) is $ d=M( \frac{1}{m}+\frac{M _2}{1000} ). $
$ M _2 $ = Mol. mass of solute On putting value $ 1.252=3( \frac{1}{m}+\frac{58.8}{1000} ) $ on solving m= 2.79
