Some Basic Concepts Of Chemistry Question 323
Question: The largest number of molecules is in [BHU 1997]
Options:
A) $ 34g $ of water
B) $ 28g $ of $ CO _2 $
C) $ 46g $ of $ CH _3OH $
D) $ 54g $ of $ N _2O _5 $
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Answer:
Correct Answer: A
Solution:
A. 34gm of water $ \because $ 18gm $ H _2O $ = $ 6.023\times 10^{23} $ molecule
$ \therefore $ 34gm $ H _2O $ = $ \frac{6.023\times 10^{23}}{18}\times 34 $
$ =11.37\times 10^{23} $ mole B. 28gm of $ CO _2 $
$ \because $ 44gm $ CO _2 $ $ =6\times 10^{23} $ molecules \ 28gm $ CO _2 $ $ =\frac{6\times 10^{23}}{44}\times 28=3.8\times 10^{23} $ C. 46gm of $ CH _3OH $
$ \because $ 32gm $ CH _3OH\ =6\times 10^{23} $ molecules \ 46gm $ CH _3OH\ =\frac{6\times 10^{23}}{32}\times 46=8.625\times 10^{23} $ D. $ \because $ 108gm of $ N _2O _5=6\times 10^{23} $ molecules \ 54gm of $ N _2O _5\ =\frac{6\times 10^{23}}{108}\times 54=3\times 10^{23} $ molecules.
