A) $ 3.0\times 10^{23} $
B) $ 6.02\times 10^{23} $
C) $ \frac{16}{6.02}\times 10^{23} $
D) $ \frac{16}{3.0}\times 10^{23} $
Correct Answer: B
16gm of $ CH _4 $ = 1mole $ =6.023\times 10^{23} $ molecules.
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