Some Basic Concepts Of Chemistry Question 281

Question: A 100 ml solution of 0.1 n HCl was titrated with 0.2 N NaOH solution. The titration was discontinued after adding 30 ml of NaOH solution. The remaining titration was completed by adding 0.25 N KOH solution. The volume of KOH required for completing the titration is [DCE 1999]

Options:

A) 70 ml

B) 32 ml

C) 35 ml

D) 16 ml

Show Answer

Answer:

Correct Answer: D

Solution:

Volume m of HCl neutralised by NaOH = (Caustic soda) = V1

N1V1=N2V2 ; 0.1×V1=0.2×30 ; V1=60ml

V total (HCl) = 100ml V1 = 60ml _________________ 40ml 40ml 0.1N HCl is now neutralised by KOH (0.25N)

(HCl) N1V1=N2V2 (KOH) 0.1×40=0.25×V2 ; V2=16ml .



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