Some Basic Concepts Of Chemistry Question 259

Question: What should be the weight and moles of AgCl precipitate obtained on adding 500ml of 0.20 M HCl in 30 g of AgNO3 solution? ( AgNO3 = 170)

Options:

A) 14.35 g

B) 15 g

C) 18 g

D) 19 g

Show Answer

Answer:

Correct Answer: A

Solution:

AgNO3+HClAgCl+HNO3

30170 500×0.21000

t =0 0.176 mole 0.1 mole limiting =14.345gm t =t 0.076 mole 0 0.1mole



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