Some Basic Concepts Of Chemistry Question 252
Question: An electric discharge is passed through a mixture containing 50 c.c. of $ O _2 $ and 50 c.c. of $ H _2 $ . The volume of the gases formed (i) at room temperature and (ii) at 1100C will be
Options:
A) (i) 25 c.c. (ii) 50 c.c.
B) (i) 50 c.c. (ii) 75 c.c.
C) (i) 25 c.c. (ii) 75 c.c.
D) (i) 75 c.c. (ii) 75 c.c.
Show Answer
Answer:
Correct Answer: C
Solution:
At room temperature $ 2{H _{2(g)}}\ \ \ +\ \ \ \ {O _{2(g)}}\ \ \to \ \ 2H _2{O _{(l)}} $
t =0 50ml 50ml 0 t =t 50 ? 2x 50 ? x 2x =0 25gases (50)liquid In this case $ H _2 $ is limiting reagent x = 25ml At 110°C $ 2{H _{2(g)}}+{O _{2(g)}}\to 2H _2{O _{(g)}} $ $ {V _{gas}}=75,ml $
t =t 0 25ml 50ml
