Some Basic Concepts Of Chemistry Question 232
Question: 0.16 g of dibasic acid required 25 ml of decinormal NaOH solution for complete neutralisation. The molecular weight of the acid will be [CPMT 1989]
Options:
A) 32
B) 64
C) 128
D) 256
Show Answer
Answer:
Correct Answer: C
Solution:
Dibasic acid NaOH; $ N _1V _1=N _2V _2 $
$ \frac{W}{E}\times 1000=\frac{1}{10}\times 25 $ ; $ \frac{0.16}{E}\times 1000=\frac{25}{10} $
$ M=2\times E=2\times 64=128 $ .