Some Basic Concepts Of Chemistry Question 231
Question: Equivalent weight of $ KMnO _4 $ acting as an oxidant in acidic medium is [CPMT 1990; MP PET 1999]
Options:
A) The same as its molecular weight
B) Half of its molecular weight
C) One-third of its molecular weight
D) One-fifth of its molecular weight
Show Answer
Answer:
Correct Answer: D
Solution:
$ \underset{+7}{\mathop{2KMnO _4}},+3H _2SO _4\to K _2SO _4+\underset{+2}{\mathop{2MnSO _4}},+3H _2O+5[O] $ $ $ $ Eq\text{. wt}\text{.}=\frac{Mol\text{. wt}\text{.}}{5} $
