Some Basic Concepts Of Chemistry Question 22

Question: The percentage of Se in peroxidase anhydrous enzyme is 0.5% by weight (atomic weight = 78.4). Then minimum molecular weight of peroxidase anhydrous enzyme is

Options:

A) $ 1.568\times 10^{3} $

B) $ 1.568\times 10^{4} $

C) 15.68

D) $ 3.136\times 10^{4} $

Show Answer

Answer:

Correct Answer: B

Solution:

[b] 0.5% by weight means of Mol. wt. is 100 then mass of Se is 0.5. If at least one atom of Se is present in the molecule then $ M.Wt=\frac{100}{0.5}\times 78.4=1.568\times 10^{4} $



जेईई के लिए मॉक टेस्ट

एनसीईआरटी अध्याय वीडियो समाधान

दोहरा फलक