Some Basic Concepts Of Chemistry Question 22
Question: The percentage of Se in peroxidase anhydrous enzyme is 0.5% by weight (atomic weight = 78.4). Then minimum molecular weight of peroxidase anhydrous enzyme is
Options:
A) $ 1.568\times 10^{3} $
B) $ 1.568\times 10^{4} $
C) 15.68
D) $ 3.136\times 10^{4} $
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Answer:
Correct Answer: B
Solution:
[b] 0.5% by weight means of Mol. wt. is 100 then mass of Se is 0.5. If at least one atom of Se is present in the molecule then $ M.Wt=\frac{100}{0.5}\times 78.4=1.568\times 10^{4} $