Some Basic Concepts Of Chemistry Question 163

Question: Boron has two stable isotopes, $ ^{10}B $ (19%) and $ ^{11}B $ (81%). The atomic mass that should appear for boron in the periodic table is [CBSE PMT 1990]

Options:

A) 10.8

B) 10.2

C) 11.2

D) 10.0

Show Answer

Answer:

Correct Answer: A

Solution:

Atomic mass $ =\frac{10\times 19+81\times 11}{100} $ $ =\frac{190+891}{100} $ $ =\frac{1081}{100} $

$ =10.81 $



जेईई के लिए मॉक टेस्ट

एनसीईआरटी अध्याय वीडियो समाधान

दोहरा फलक