Some Basic Concepts Of Chemistry Question 12
Question: 1.0 g of a monobasic acid when completely acted upon Mg gave 1.301 g of anhydrous Mg salt. Equivalent weight of acid is
Options:
A) 35.54
B) 36.54
C) 17.77
D) 18.27
Show Answer
Answer:
Correct Answer: B
Solution:
$ \frac{Ew,of,acid}{Ew,of,salt,of,Mg} $ = $ \frac{weight,of,acid}{Weight,of,slt} $ Mg+2HCl (monobasic acid) $ \to $ $ MgCl _2 $ + $ H _2 $ Let Ew of acid=Ew of H + Ew of acid radical
$ \therefore $ Ew of salt of Mg = Ew of Mg + Ew of acid radical
$ \therefore $ $ \frac{Ew,of,acid}{Ew,of,Mg,salt} $ = $ \frac{weight,of,acid}{Weight,of,Mg,salt} $
$ \Rightarrow $ $ \frac{Ew,of,H+Ew,of,acid,radical,(E)}{Ew,of,Mg,+Ew,of,acid,radical,(E)} $ = $ \frac{1.0}{1.301} $
$ \Rightarrow $ $ \frac{1+E}{12+E}=\frac{1.0}{1.301} $
$ \therefore $ E=35 , 54
$ \therefore $ EW of acid = Ew of H + Ew of acid radical =1+35.54=36.54
