Some Basic Concepts Of Chemistry Question 12

Question: 1.0 g of a monobasic acid when completely acted upon Mg gave 1.301 g of anhydrous Mg salt. Equivalent weight of acid is

Options:

A) 35.54

B) 36.54

C) 17.77

D) 18.27

Show Answer

Answer:

Correct Answer: B

Solution:

$ \frac{Ew,of,acid}{Ew,of,salt,of,Mg} $ = $ \frac{weight,of,acid}{Weight,of,slt} $ Mg+2HCl (monobasic acid) $ \to $ $ MgCl _2 $ + $ H _2 $ Let Ew of acid=Ew of H + Ew of acid radical
$ \therefore $ Ew of salt of Mg = Ew of Mg + Ew of acid radical
$ \therefore $ $ \frac{Ew,of,acid}{Ew,of,Mg,salt} $ = $ \frac{weight,of,acid}{Weight,of,Mg,salt} $
$ \Rightarrow $ $ \frac{Ew,of,H+Ew,of,acid,radical,(E)}{Ew,of,Mg,+Ew,of,acid,radical,(E)} $ = $ \frac{1.0}{1.301} $
$ \Rightarrow $ $ \frac{1+E}{12+E}=\frac{1.0}{1.301} $
$ \therefore $ E=35 , 54
$ \therefore $ EW of acid = Ew of H + Ew of acid radical =1+35.54=36.54



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