Some Basic Concepts Of Chemistry Question 103
Question: Vapour density of a metal chloride is 66. Its oxide contains 53% metal. The atomic weight of the metal is
Options:
A) 21
B) 54
C) 27.06
D) 2.086
Show Answer
Answer:
Correct Answer: C
Solution:
[c] Let wt. of metal oxide = 100gm
wt. of metal = 53gm
wt. of oxygen = 47gm
Equivalent weight of oxygen $ =\frac{wt\text{. of metal}}{wt\text{. of oxygen}}\times 8 $
$ =\frac{53}{47}\times 8=9.02 $
Valency $ =\frac{2\times V.D}{E+35.5}=\frac{2\times 66}{9+35.5}=\frac{132}{44.5}=2.96\approx 3 $
$ \therefore $ Atomic weight $ =\text{Equivalent weight}\times Valency $
$ =9.02\times 3=27.06 $
