Solutions Question 83
Question: The latent heat of vapourisation of water is $ 9700,Cal/mole $ and if the b.p. is $ 100^{o}C $ , ebullioscopic constant of water is [CBSE PMT 1989]
Options:
A) $ {{0.513}^{o}}C $
B) $ {{1.026}^{o}}C $
C) $ {{10.26}^{o}}C $
D) $ {{1.832}^{o}}C $
Show Answer
Answer:
Correct Answer: A
Solution:
$ K_{b}=\frac{M_1RT_0^{2}}{1000\Delta H_{V}}=\frac{18\times 1.987\times {{(373)}^{2}}}{1000\times 9700} $
$ ={{0.513}^{o}}C $
