Solutions Question 399

Question: The relative lowering of vapour pressure of aqueous solution containing a non-volatile solute is 0.0125. The molality of the solution is

Options:

A) 0.70

B) 0.50

C) 0.80

D) 0.40

Show Answer

Answer:

Correct Answer: A

Solution:

$ \frac{p{}^\circ -p}{p{}^\circ }=X_1=0.0125= $ mole fraction of solute

Mole fraction and molarity are related as

$ \frac{1}{X}-1=\frac{1000}{M\times m} $ $ \frac{1}{0.0125}-1=\frac{1000}{18\times m} $ $ m=0.70 $



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