Solutions Question 366
Question: The osmotic pressure (at $ 27{}^\circ C $ ) of an aqueous solution (200mL) containing 6g of a protein is $ 2\times {10^{-3}} $ atm. If R= 0.080 L atm $ mo{l^{-1}}{K^{-1}} $ , the molecular weight of protein is
Options:
A) $ 7.2\times 10^{5} $
B) $ 3.6\times 10^{5} $
C) $ 1.8\times 10^{5} $
D) $ 1.0\times 10^{5} $
Show Answer
Answer:
Correct Answer: B
Solution:
Using the relation, $ M=\frac{w.R.T}{\pi V}, $ We get $ M=\frac{6\times 0.080\times 300}{2\times {10^{-3}}\times 0.2}=3.6\times 10^{5} $
