Solutions Question 364
Question: At 760 torr pressure and $ 20{}^\circ C $ temperature, 1 L of water dissolves 0.04 gm of pure oxygen or 0.02 gm of pure nitrogen. Assuming that dry air is composed of 20% oxygen and 80% nitrogen (by volume), the masses (in g/L) of oxygen and nitrogen dissolved by 1 L of water at $ 20{}^\circ C $ exposed to air at a total pressure of 760 torr are respectively:
Options:
A) 0.008, 0.016
B) 0.016, 0.008
C) 0.16, 0.08
D) 0.04, 0.02
Show Answer
Answer:
Correct Answer: A
Solution:
Mass of oxygen $ =\frac{20}{100}\times 0.04=0.008g/L $ Mass of nitrogen $ =\frac{80}{100}\times 0.02=0.016g/L $
