Solutions Question 349

Question: 200 mL of an aqueous solution of a protein contains its 1.26 g. The osmotic pressure of this solution at 300 K is found to be 2.57×103 bar. The molar mass of protein will be (R = 0.083 L bar mol1K1 )

Options:

A) 51022gmol1

B) 122044gmol1

C) 31011g,mol1

D) 61038g,mol1

Show Answer

Answer:

Correct Answer: D

Solution:

Osmotic pressure (π)=CRT

(π)=wt×1000Molecularmass×VRT

=2.57×103=26×1000Mol.mass×200×0.083×300 Molecular mass = 61038 g



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