Solutions Question 349
Question: 200 mL of an aqueous solution of a protein contains its 1.26 g. The osmotic pressure of this solution at 300 K is found to be $ 2.57\times {10^{-3}} $ bar. The molar mass of protein will be (R = 0.083 L bar $ mo{l^{-1}}{K^{-1}} $ )
Options:
A) $ 51022gmo{l^{-1}} $
B) $ 122044gmo{l^{-1}} $
C) $ 31011g,mo{l^{-1}} $
D) $ 61038g,mo{l^{-1}} $
Show Answer
Answer:
Correct Answer: D
Solution:
Osmotic pressure $ ( \pi )=CRT $
$ (\pi )=\frac{wt\times 1000}{Molecularmass\times V}RT $
$ =2.57\times {10^{-3}}=\frac{26\times 1000}{Mol.mass\times 200}\times 0.083\times 300 $ Molecular mass = 61038 g
