Solutions Question 22
Question: In equimolar solution of glucose, $ NaCl $ and $ BaCl_2 $ , the order of osmotic pressure is as follow [CPMT 1988, 93; MP PMT/PET 1988; MP PET 1997, 2003]
Options:
A) Glucose $ >,NaCl>BaCl_2 $
B) $ NaCl>BaCl_2> $ Glucose
C) $ BaCl_2>NaCl> $ Glucose
D) Glucose $ >BaCl_2>NaCl $
Show Answer
Answer:
Correct Answer: C
Solution:
$ BaCl_2 $
Þ $ B{a^{2+}}+2C{l^{-}}=3 $ ion $ NaCl $
Þ $ N{a^{+}}+C{l^{-}}=2 $ ion Glucose
Þ No ionisation \ $ BaCl_2>NaCl>Glucose $
