Solutions Question 199

Question: When $ 1.80gm $ glucose dissolve in $ 90,gm $ of $ H_2O $ , the mole fraction of glucose is [AFMC 2000]

Options:

A) 0.00399

B) 0.00199

C) 0.0199

D) 0.998

Show Answer

Answer:

Correct Answer: B

Solution:

Mole fraction of glucose = $ \frac{n}{n+N} $ = $ \frac{0.01}{0.01+5}=0.00199 $



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