Solutions Question 199
Question: When $ 1.80gm $ glucose dissolve in $ 90,gm $ of $ H_2O $ , the mole fraction of glucose is [AFMC 2000]
Options:
A) 0.00399
B) 0.00199
C) 0.0199
D) 0.998
Show Answer
Answer:
Correct Answer: B
Solution:
Mole fraction of glucose = $ \frac{n}{n+N} $ = $ \frac{0.01}{0.01+5}=0.00199 $