Solutions Question 183
Question: 1.0 gm of pure calcium carbonate was found to require 50 ml of dilute $ HCl $ for complete reaction. The strength of the $ HCl $ solution is given by [CPMT 1986]
Options:
A) 4 N
B) 2 N
C) 0.4 N
D) 0.2 N
Show Answer
Answer:
Correct Answer: C
Solution:
M.eq. of HCl = M.eq. of $ CaCO_3 $
$ N\times 50=\frac{1}{50}\times 1000 $ ; $ N=\frac{1\times 1000}{50\times 50}=0.4N $
