Solutions Question 159

Question: How many gram of HCl will be present in $ 150,ml $ of its 0.52 M solution [RPET 1999]

Options:

A) 2.84 gm

B) 5.70 gm

C) 8.50 gm

D) 3.65 gm

Show Answer

Answer:

Correct Answer: A

Solution:

$ M=\frac{w}{m\times V(l)} $ ; $ 0.52=\frac{w}{36.5\times 0.15} $ ; $ w=2.84,gm $



जेईई के लिए मॉक टेस्ट

एनसीईआरटी अध्याय वीडियो समाधान

दोहरा फलक