Solutions Question 159

Question: How many gram of HCl will be present in 150,ml of its 0.52 M solution [RPET 1999]

Options:

A) 2.84 gm

B) 5.70 gm

C) 8.50 gm

D) 3.65 gm

Show Answer

Answer:

Correct Answer: A

Solution:

M=wm×V(l) ; 0.52=w36.5×0.15 ; w=2.84,gm



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