Solutions Question 159
Question: How many gram of HCl will be present in $ 150,ml $ of its 0.52 M solution [RPET 1999]
Options:
A) 2.84 gm
B) 5.70 gm
C) 8.50 gm
D) 3.65 gm
Show Answer
Answer:
Correct Answer: A
Solution:
$ M=\frac{w}{m\times V(l)} $ ; $ 0.52=\frac{w}{36.5\times 0.15} $ ; $ w=2.84,gm $