Solutions Question 121

Question: The vapour pressure of pure liquid A is 0.80 atm. On mixing a non-volatile B to A, its vapour pressure becomes 0.6 atm. The mole fraction of B in the solution is [MP PET 2003]

Options:

A) 0.150

B) 0.25

C) 0.50

D) 0.75

Show Answer

Answer:

Correct Answer: B

Solution:

According to Raoul’s Law $ \frac{P^{0}-P_{s}}{P^{0}}=x_{B} $ (Mole fraction of solute) $ x_{B}=\frac{0.8-0.6}{0.8}=0.25 $ .



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