Solutions Question 100

Question: Which of the following liquid pairs shows a positive deviation from Raoult’s law [MP PET 1993; UPSEAT 2001; AIEEE 2004]

Options:

A) Water-nitric acid

B) Benzene-methanol

C) Water-hydrochloric acid

D) Acetone-chloroform

Show Answer

Answer:

Correct Answer: B

Solution:

In solution showing positive type of deviation the partial pressure of each component of solution is greater than the vapour pressure as expected according to Raoul’s law. In solution of methanol & benzene methanol molecules are held together due to hydrogen bonding as shown below. $ —\overset{\begin{matrix} CH_3 \\ | \\ \end{matrix}}{\mathop{O}},-H—\overset{\begin{matrix} CH_3 \\ | \\ \end{matrix}}{\mathop{O}},-H—\overset{\begin{matrix} CH_3 \\ | \\ \end{matrix}}{\mathop{O}},-H— $ On adding benzene, the benzene molecules get in between the molecule of methanol thus breaking the hydrogen bonds. As the resulting solution has weak intermolecular attraction, the escaping tendency of alcohol & benzene molecule from the solution increases. Consequently the vapour pressure of the solution is greater than the vapour pressure as expected from Raoul’s law.



जेईई के लिए मॉक टेस्ट

एनसीईआरटी अध्याय वीडियो समाधान

दोहरा फलक