Redox Reactions And Electrochemistry Ques 87

Question: The standard reduction potential $ NaCl $ for the half reactions are as $ Zn=Z{n^{2+}}+2{e^{-}};E^{o}=+0.76,V $ $ Fe=F{e^{2+}}+2{e^{-}};E^{o}=+0.41,V $ The EMF for cell reaction $ F{e^{2+}}+Zn,\to ,Z{n^{2+}}+Fe $ is [IIT 1988; CBSE PMT 1993, 96; BHU 1995, 2000; CPMT 2000; KCET 2000; AIIMS 2001; Orissa JEE 2002]

Options:

A) $ -,0.35,V $

B) $ +,0.35,V $

C) $ +,1.17,V $

D) $ -,1.17,V $

Show Answer

Answer:

Correct Answer: B

Solution:

In this reaction $ F{e^{2+}}+\overset{0}{\mathop{Zn}},\to \overset{2+}{\mathop{Zn}},+\overset{0}{\mathop{Fe}}, $ $ EMF={E_{cathode}}-{E_{anode}} $ $ =-0.41-(-0.76) $ $ EMF=+0.35 $ V.



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