SATHEE: Redox Reactions And Electrochemistry Ques 84

Redox Reactions And Electrochemistry Ques 84

Question: The limiting molar conductivities $\land^{0}$ for NaCl, KBr and KCl are 126, 152 and 150 $S c m^{2} m o l^{- 1}$ respectively. The $\land^{0}$ for NaBr is [AIEEE 2004]

Options:

A) $278 S c m^{2} m o l^{- 1}$

B) $176 S c m^{2} m o l^{- 1}$

C) $128 S c m^{2} m o l^{- 1}$

D) $302 S c m^{2} m o l^{- 1}$

Show Answer

Answer:

Correct Answer: C

Solution:

$(126 s c m^{2}) \land_{N} a C l^{0} = \land_{N a^{+}}^{0} + \land_{C l^{-}}^{0}$ …..(1)

$(152 s c m^{2}) \land_{K} B r^{0} = \land_{K^{+}}^{0} + \land_{B r^{-}}^{0}$ …..(2)

$(150 s c m^{2}) \land_{K} C l^{0} = \land_{K^{+}}^{0} + \land_{C l^{-}}^{0}$ …..(3)

By equation (1)+(2) - (3)

$∵$ $\land_{N a B r}^{0} = \land_{N a^{+}}^{0} + \land_{B r^{-}}^{0}$

$= 126 + 152 - 150 = 128 S c m^{2}, m o l^{- 1}$

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Redox Reactions And Electrochemistry Ques 84

Question: The limiting molar conductivities $\land^{0}$ for NaCl, KBr and KCl are 126, 152 and 150 $S c m^{2} m o l^{- 1}$ respectively. The $\land^{0}$ for NaBr is [AIEEE 2004]

Options:

Answer:

Solution:

इंजीनियरिंग की तैयारी

चिकित्सा तैयारी

एनसीईआरटी पुस्तकें और समाधान

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परीक्षा मंच

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सदस्यता

एनसीईआरटी व्यायाम वीडियो समाधान

Redox Reactions And Electrochemistry Ques 84

Question: The limiting molar conductivities ∧0 for NaCl, KBr and KCl are 126, 152 and 150 S cm2mol−1 respectively. The ∧0 for NaBr is [AIEEE 2004]

Options:

Answer:

Solution:

इंजीनियरिंग की तैयारी

चिकित्सा तैयारी

एनसीईआरटी पुस्तकें और समाधान

महत्वपूर्ण संसाधन

अन्य संसाधन

पाठ्यक्रम

परीक्षा मंच

नमूना मॉक टेस्ट

सदस्यता

एनसीईआरटी व्यायाम वीडियो समाधान

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Question: The limiting molar conductivities $\land^{0}$ for NaCl, KBr and KCl are 126, 152 and 150 $S c m^{2} m o l^{- 1}$ respectively. The $\land^{0}$ for NaBr is [AIEEE 2004]