Redox Reactions And Electrochemistry Ques 771

Question: What will be the value of x, y and z in the following equation $ H_2C_2O_4+xH_2O_2\xrightarrow[{}]{{}} $ $ yCO_2+zH_2O $

Options:

A) 2, 1, 2

B) 1, 2, 2

C) 2, 2, 1

D) None of these

Show Answer

Answer:

Correct Answer: B

Solution:

[b] (i) The half reaction for oxidation is, $ H_2C_2O_4\xrightarrow[{}]{{}}CO_2 $

Balancing carbon atoms on both sides, $ H_2C_2O_4\xrightarrow[{}]{{}}2CO_2 $

Balancing hydrogen atoms on both sides, $ H_2C_2O_4\xrightarrow[{}]{{}}2CO_2+2{{H}^{+}} $

Balancing the charge on both sides, $ H_2C_2O_4\xrightarrow[{}]{{}}2CO_2+2{{H}^{+}}+2{{e}^{-}} $ (balanced)

(ii) The half reaction for reduction is- $ H_2O_2\xrightarrow[{}]{{}}H_2O $

Balancing oxygen atoms on both sides, $ H_2O_2\xrightarrow[{}]{{}}2H_2O $

Balancing hydrogen atoms, $ H_2O_2+2{{H}^{+}}\xrightarrow[{}]{{}}2H_2O $

Balancing the charge, $ H_2O_2+2{{H}^{+}}+2{{e}^{-}}\xrightarrow[{}]{{}}2H_2O $(balanced)

Now, adding both equation, $ H_2C_2O_4+H_2O_2\xrightarrow[{}]{{}}2CO_2+2H_2O $ This is balanced equation.



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