SATHEE: Redox Reactions And Electrochemistry Ques 734

Redox Reactions And Electrochemistry Ques 734

Question: Resistance of a conductivity cell filled with a solution of an electrolyte of concentration 0.1 M is 100 ohm. The conductivity of this solution is 1.29 S/m. Resistance of the same cell filled with 0.02 M of the same solution if the electrolyte is 520 ohm. The molar conductivity of 0.02 M solution of electrolyte would be:

Options:

A) $124 \times 10^{- 4} S - m^{2} / m o l$

B) $1240 \times 10^{- 4} S - m^{2} / m o l$

C) $1.24 \times 10^{- 4} S - m^{2} / m o l$

D) $12.4 \times 10^{- 4} S - m^{2} / m o l$

Show Answer

Answer:

Correct Answer: A

Solution:

[a] at $c = 0.1, M;$ $\frac{l}{a} = k R = 1.29 \times 100$ at $c = 0.02 M;$ $κ = \frac{ℓ}{a \times R} = \frac{1.29 \times 100}{520} = 0.248, S / m$ Also, $Λ = \frac{k}{M (i n, m o l / l)} = \frac{k}{M \times 10^{3} (i n, m o l / m^{3})}$ $= \frac{0.248}{0.02 \times 10^{3}} = 124 \times 10^{- 4} S m^{2} / m o l$

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Redox Reactions And Electrochemistry Ques 734

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