Redox Reactions And Electrochemistry Ques 720

Question: The standard electrode potential for the following reaction is + 1.33 V. What is the potential at pH = 2- $ Cr_2O_7^{2-}(aq1M)+14{H^{\oplus }}(aq)+6{e^{-}} $ $ \xrightarrow{,},2C{r^{3+}}(aq1M)+7H_2O(l) $

Options:

A) +1.82 V

B) +1.99 V

C) +1.608 V

D) +1.054 V

Show Answer

Answer:

Correct Answer: D

Solution:

[d] $ {E_{Cr_2O_7^{2-}/C{r^{3+}}}} $ $ =E_{Cr_2O_7^{2-}/C{r^{3+}}}^{o}-\frac{0.0591}{6}\log \frac{{{[C{r^{3+}}]}^{2}}}{[Cr_2O_7^{2-}]{{[{H^{+}}]}^{14}}} $ $ =1.33-\frac{0.0591}{6}\log \frac{1}{{{(0.01)}^{14}}} $ $ =1.0542V $



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