SATHEE: Redox Reactions And Electrochemistry Ques 720

Redox Reactions And Electrochemistry Ques 720

Question: The standard electrode potential for the following reaction is + 1.33 V. What is the potential at pH = 2- $C r_{2} O_{7}^{2 -} (a q 1 M) + 14 H^{\oplus} (a q) + 6 e^{-}$ $\overset{,}{\to}, 2 C r^{3 +} (a q 1 M) + 7 H_{2} O (l)$

Options:

A) +1.82 V

B) +1.99 V

C) +1.608 V

D) +1.054 V

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Answer:

Correct Answer: D

Solution:

[d] $E_{C r_{2} O_{7}^{2 -} / C r^{3 +}}$ $= E_{C r_{2} O_{7}^{2 -} / C r^{3 +}}^{o} - \frac{0.0591}{6} \log \frac{{[C r^{3 +}]}^{2}}{[C r_{2} O_{7}^{2 -}] {[H^{+}]}^{14}}$ $= 1.33 - \frac{0.0591}{6} \log \frac{1}{{(0.01)}^{14}}$ $= 1.0542 V$

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Redox Reactions And Electrochemistry Ques 720

Question: The standard electrode potential for the following reaction is + 1.33 V. What is the potential at pH = 2- Cr2O72−(aq1M)+14H⊕(aq)+6e− →,,2Cr3+(aq1M)+7H2O(l)

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Question: The standard electrode potential for the following reaction is + 1.33 V. What is the potential at pH = 2- $C r_{2} O_{7}^{2 -} (a q 1 M) + 14 H^{\oplus} (a q) + 6 e^{-}$ $\overset{,}{\to}, 2 C r^{3 +} (a q 1 M) + 7 H_{2} O (l)$