Redox Reactions And Electrochemistry Ques 653
Question: A compound of Xe and F is found to have 53.5% of Xe. What is oxidation number of Xe in this compound-
Options:
A) - 4
B) 0
C) +4
D) +6
Show Answer
Answer:
Correct Answer: D
Solution:
[d] $ Xe=53.5%,\therefore F=46.5% $ Relative number of atoms Xe $ =\frac{53.5}{131.2}=0.4 $ and $ F=\frac{46.5}{19}=2.4 $ Simple ratio Xe = 1 and F = 6 ; Molecular formula is $ XeF_6 $ O.N. of Xe is+6
