Redox Reactions And Electrochemistry Ques 646
Question: The solution of $ CuSO_4 $ in which copper rod is immersed is diluted to 10 times. The reduction electrode potential
Options:
A) Increases by $ 30mV $
B) Decreases by $ 30mV $
C) Increases by $ 59mV $
D) Decreases by $ 59mV $
Show Answer
Answer:
Correct Answer: B
Solution:
[b] $ {{({E _{C{u^{2+}}/Cu}})} _1}=E^0 _{C{u^{2+}}/Cu}+\frac{0.059}{2}\log {{[C{u^{2+}}]} _1} $
$ [C{u^{2+}}(aq)+2{e^{-}}\xrightarrow{{}}Cu(s) $ and $ {{({E _{C{u^{2+}}/Cu}})} _2}=E^0 _{C{u^{2+}}/Cu}+\frac{0.059}{2}\log {{[C{u^{2+}}]} _2} $
$ \Rightarrow \Delta {E _{C{u^{2+}}/Cu}}=-\frac{0.059}{2}\log ( \frac{C_2}{C_1} ) $ $ =-\frac{0.059}{2}log,10=-0.030V=-30,mV $
