SATHEE: Redox Reactions And Electrochemistry Ques 640

Redox Reactions And Electrochemistry Ques 640

Question: Equivalent conductance at infinite dilution, $λ^{^{\circ}}$ of $N H_{4} C l,, N a O H$ and $N a C l$ are 128.0,217.8 and $109.3 o h m^{- 1} c m^{2} e q^{- 1}$ respectively. The equivalent conductance of $0.01 N N H_{2} O H$ is $9.30 o h m^{- 1}, c m^{2} e q^{- 1}$ then the degree of ionization of $N H_{4} O H$ at this temperature would be

Options:

A) 0.04

B) 0.1

C) 0.39

D) 0.62

Show Answer

Answer:

Correct Answer: A

Solution:

[a] $Λ_{e} q^{\infty} (N H_{4} O H) = Λ_{e} q^{\infty} (N H_{4} C l) + Λ_{e} q^{\infty} (N a O H) - Λ_{e} q^{\infty} (N a C l)$

$= 129.8 + 217.8 - 109.3 = 238.3 o h m^{- 1} c m^{2} e q^{- 1}$

$α = \frac{Λ_{e q}}{Λ_{e} q^{\infty}} = \frac{9.30}{238.3} = 0.04$

पिछला

अगला

गोपनीयता नीति

द्वारा संचालित Prutor@IITK

sathee@iitk.ac.in

SATHEE का मीडिया कवरेज

खेल स्टोर

ऐप स्टोर

Ask SATHEE

Welcome to SATHEE !
Select from 'Menu' to explore our services, or ask SATHEE to get started. Let's embark on this journey of growth together! 🌐📚🚀🎓

I'm relatively new and can sometimes make mistakes.
If you notice any error, such as an incorrect solution, please use the thumbs down icon to aid my learning.
To begin your journey now, click on "I understand".

Redox Reactions And Electrochemistry Ques 640

Question: Equivalent conductance at infinite dilution, λ∘ of NH4Cl,,NaOH and NaCl are 128.0,217.8 and 109.3ohm−1cm2eq−1 respectively. The equivalent conductance of 0.01NNH2OH is 9.30ohm−1,cm2eq−1 then the degree of ionization of NH4OH at this temperature would be

Options:

Answer:

Solution:

इंजीनियरिंग की तैयारी

चिकित्सा तैयारी

एनसीईआरटी पुस्तकें और समाधान

महत्वपूर्ण संसाधन

अन्य संसाधन

पाठ्यक्रम

परीक्षा मंच

नमूना मॉक टेस्ट

सदस्यता

एनसीईआरटी व्यायाम वीडियो समाधान

Menu