Redox Reactions And Electrochemistry Ques 587
Question: Given the ionic conductance of , $ {K^{+}} $ , and $ N{a^{+}} $ are 74, 50, and $ 73cm^{2}oh{m^{-1}} $ $ e{q^{-1}} $ respectively. The equivalent conductance at infinite dilution of the salt is
Options:
A) $ 197cm^{2}oh{m^{-1}}e{q^{-1}} $
B) $ 172,cm^{2}oh{m^{-1}}e{q^{-1}} $
C) $ 135.5,cm^{2}oh{m^{-1}}e{q^{-1}} $
D) $ 160.5,cm^{2}oh{m^{-1}}e{q^{-1}} $
Show Answer
Answer:
Correct Answer: C
Solution:
[c] Total charge =2 Number of equivalent of ion $ =\frac{Chargeontheion}{Totalcharge} $
$ \therefore Eq $ of $ =\frac{2}{2}=1 $ Eq of $ N{a^{+}}=\frac{1}{2},Eqof,{K^{+}}=\frac{1}{2} $ $ =74+\frac{50}{2}+\frac{73}{2}=135.5oh{m^{-1}}cm^{2}e{q^{-1}} $
