Redox Reactions And Electrochemistry Ques 573

Question: The limiting equivalent conductivity of $ NaCl,~KCl $ and $ KBr $ are 126.5, 150.0 and $ 151.5Scm^{2}e{q^{-1}} $ , respectively. The limiting equivalent ionic conductivity for $ B{r^{-}} $ is $ 78,Scm^{2}e{q^{-1}} $ . The limiting equivalent ionic conductivity for $ N{a^{+}} $ ions would be:

Options:

A) 128

B) 125

C) 49

D) 50

Show Answer

Answer:

Correct Answer: D

Solution:

[d] $ \Lambda _m^{\infty }(NaBr)=\Lambda _m^{\infty }(NaCl)+\Lambda _m^{\infty }KBr-\Lambda _m^{\infty }(KCl) $ $ \lambda _m^{\infty }(N{a^{+}})+\lambda _m^{\infty }(B{r^{-}})=126.5+151.5-150 $ $ \lambda _m^{\infty }(N{a^{+}})=50,Scm^{2}e{q^{-1}}. $



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