Redox Reactions And Electrochemistry Ques 571
Question: If 0.01 M solution of an electrolyte has a resistance of 40 ohms in a cell having a cell constant of $ 0.4c{m^{-1}}, $ then its molar conductance in $ oh{m^{-1}}cm^{2}mo{l^{-1}} $ is
Options:
A) $ 10^{2} $
B) $ 10^{4} $
C) 10
D) $ 10^{3} $
Show Answer
Answer:
Correct Answer: D
Solution:
[d] Molarity = 0.01 M ; Resistance = 40 ohm; Cell constant $ \frac{l}{A}=0.4,c{m^{-1}}. $ Specific conductivity (k) $ =\frac{\text{cell constant}}{resistance}=\frac{0.4}{40}=0.01oh{m^{-1}},c{m^{-1}} $
$ \text{Molar conductance}( {\wedge_{m}} )=\frac{1000\kappa }{Molarity} $ . $ =\frac{1000\times 0.01}{0.01}=10^{3}oh{m^{-1}}cm^{2}mo{l^{-1}} $
