SATHEE: Redox Reactions And Electrochemistry Ques 571

Redox Reactions And Electrochemistry Ques 571

Question: If 0.01 M solution of an electrolyte has a resistance of 40 ohms in a cell having a cell constant of $0.4 c m^{- 1},$ then its molar conductance in $o h m^{- 1} c m^{2} m o l^{- 1}$ is

Options:

A) $10^{2}$

B) $10^{4}$

C) 10

D) $10^{3}$

Show Answer

Answer:

Correct Answer: D

Solution:

[d] Molarity = 0.01 M ; Resistance = 40 ohm; Cell constant $\frac{l}{A} = 0.4, c m^{- 1} .$ Specific conductivity (k) $= \frac{cell constant}{r e s i s t a n c e} = \frac{0.4}{40} = 0.01 o h m^{- 1}, c m^{- 1}$

$Molar conductance (\land_{m}) = \frac{1000 κ}{M o l a r i t y}$ . $= \frac{1000 \times 0.01}{0.01} = 10^{3} o h m^{- 1} c m^{2} m o l^{- 1}$

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Redox Reactions And Electrochemistry Ques 571

Question: If 0.01 M solution of an electrolyte has a resistance of 40 ohms in a cell having a cell constant of 0.4cm−1, then its molar conductance in ohm−1cm2mol−1 is

Options:

Answer:

Solution:

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Question: If 0.01 M solution of an electrolyte has a resistance of 40 ohms in a cell having a cell constant of $0.4 c m^{- 1},$ then its molar conductance in $o h m^{- 1} c m^{2} m o l^{- 1}$ is