SATHEE: Redox Reactions And Electrochemistry Ques 569

Redox Reactions And Electrochemistry Ques 569

Question: Given that: $E {^{\circ}}_{A g^{+} / A g} = 0.80 V$ and $[A g^{+}] = 10^{- 3} M;$ $E {^{\circ}}_{H g_{2}^{2 +} / H g} = 0.785 V$ and $[H g_{2}^{2 +}] = 10^{- 1} M$ which is true for the cell reaction $2 H g (l) + 2 A g^{+} (a q) \to 2 A g (s) + H g_{2}^{2 +} (a q) -$

Options:

A) The forward reaction is spontaneous

B) The backward reaction is spontaneous

C) $E_{c e l l} = 0.163, ν$

D) $E_{c e l l} = 1.585, ν$

Show Answer

Answer:

Correct Answer: B

Solution:

[b] $E_{c e l l} = E_{c e l l}^{^{\circ}} - \frac{0.0592}{2} \log \frac{[H g_{2}^{2 +} (a q)]}{{[A g^{+} (a q)]}^{2}}$ $= (0.80 - 0.785) - \frac{0.0592}{2} l o g \frac{10^{- 1}}{{(10^{- 3})}^{2}} = - 0.133 V$ hence backward reaction is spontaneous.

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Redox Reactions And Electrochemistry Ques 569

Question: Given that: $E {^{\circ}}_{A g^{+} / A g} = 0.80 V$ and $[A g^{+}] = 10^{- 3} M;$ $E {^{\circ}}_{H g_{2}^{2 +} / H g} = 0.785 V$ and $[H g_{2}^{2 +}] = 10^{- 1} M$ which is true for the cell reaction $2 H g (l) + 2 A g^{+} (a q) \to 2 A g (s) + H g_{2}^{2 +} (a q) -$

Options:

Answer:

Solution:

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Redox Reactions And Electrochemistry Ques 569

Question: Given that: E∘Ag+/Ag =0.80V and [Ag+]=10−3M; E∘Hg22+/Hg=0.785V and [Hg22+]=10−1M which is true for the cell reaction 2Hg(l)+2Ag+(aq)→2Ag(s)+Hg22+(aq)−

Options:

Answer:

Solution:

इंजीनियरिंग की तैयारी

चिकित्सा तैयारी

एनसीईआरटी पुस्तकें और समाधान

महत्वपूर्ण संसाधन

अन्य संसाधन

पाठ्यक्रम

परीक्षा मंच

नमूना मॉक टेस्ट

सदस्यता

एनसीईआरटी व्यायाम वीडियो समाधान

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Question: Given that: $E {^{\circ}}_{A g^{+} / A g} = 0.80 V$ and $[A g^{+}] = 10^{- 3} M;$ $E {^{\circ}}_{H g_{2}^{2 +} / H g} = 0.785 V$ and $[H g_{2}^{2 +}] = 10^{- 1} M$ which is true for the cell reaction $2 H g (l) + 2 A g^{+} (a q) \to 2 A g (s) + H g_{2}^{2 +} (a q) -$