Redox Reactions And Electrochemistry Ques 49
Question: $ {\lambda_{ClCH_2COONa}}=224,oh{m^{-1}}cm^{2}gme{q^{-1}} $ , $ {\lambda_{NaCl}}=38.2,oh{m^{-1}}cm^{2}gme{q^{-1}} $ , $ {\lambda_{HCl}}=203,oh{m^{-1}}cm^{2}gme{q^{-1}} $ , What is the value of $ {\lambda_{ClCH_2COOH}} $ [JEE Orissa 2004]
Options:
A) $ 288.5\ oh{m^{-1}}cm^{2}gme{q^{-1}} $
B) $ 289.5\ oh{m^{-1}}cm^{2}gme{q^{-1}} $
C) $ 388.5\ oh{m^{-1}}cm^{2}gme{q^{-1}} $
D) $ 59.5\ oh{m^{-1}}cm^{2}gme{q^{-1}} $
Show Answer
Answer:
Correct Answer: C
Solution:
$ Cl\underset{{\lambda_{ClCH_2COONa}}+}{\mathop{CH_2COONa}},+\underset{{\lambda_{HCl}}}{\mathop{HCl}},\underset{=}{\mathop{\to }},\underset{{\lambda_{ClCH_2COOH}}+}{\mathop{ClCH_2COOH}},+\underset{{\lambda_{NaCl}}}{\mathop{NaCl}}, $ $ 224+203={\lambda_{ClCH_2COOH}}+38.2 $ $ {\lambda_{ClCH_2COOH}}=427-38.2=388.8\ oh{m^{-1}}cm^{2}gme{q^{-1}} $ .
