Redox Reactions And Electrochemistry Ques 432
Question: The oxidation state of nitrogen is highest in [MP PMT 2001; BHU 2002]
Options:
A) $ N_3H $
B) $ NH_2OH $
C) $ N_2H_4 $
D) $ NH_3 $
Show Answer
Answer:
Correct Answer: A
Solution:
$ 3\times x+1,(1)=0 $ $ 3x+1=0 $
$ 3x=-1,,\Rightarrow x=-\frac{1}{3}inN_3H $
$ x+2,(+1)+1,(-2)+1(1)=0 $
$ x=-1inNH_2OH $
$ x\times 2+4,(1)=0 $ $ x=-\frac{4}{2}=-2,inN_2H_4 $
$ x+3,(1)=0 $ $ x=-3inNH_3 $
Hence, highest in $ N_3H $ .
