Redox Reactions And Electrochemistry Ques 395
Question: The oxidation number of S in $ H_2S_2O_8 $ is [MP PET 2002]
Options:
A) + 2
B) + 4
C) + 6
D) + 7
Show Answer
Answer:
Correct Answer: C
Solution:
The chemical structure of $ H_2S_2O_8 $ is as follows:- $ H-O-\underset{O}{\overset{O}{\mathop{\underset{||}{\overset{||}{\mathop{S}}},}}},-O-O-\underset{O}{\overset{O}{\mathop{\underset{||}{\overset{||}{\mathop{S}}},}}},-O-H $ So the oxidation number of S should be : $ \underset{(forH)}{\mathop{2\times (+1)}},+\underset{(forS)}{\mathop{2\times X}},+\underset{(forO)}{\mathop{6\times (-2)}},+\underset{(forO-O)}{\mathop{2\times (-1)}},=0 $ or $ X=+6 $ .
