Redox Reactions And Electrochemistry Ques 357
Question: Which of the following has been arranged in order of increasing oxidation number of nitrogen-
Options:
A) $ NH_3<N_2O_5<NO<N_2 $
B) $ N{{O}^{+}}_2<N{{O}^{-}}_3<N{{O}^{-}}_2<{{N}^{-}}_3 $
C) $ N{{H}^{+}}_4<N_2H_4<NH_2OH<N_2O $
D) $ NO_3<NaN_3<N{{H}^{+}}_4<N_2O $
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Answer:
Correct Answer: C
Solution:
[c] [a] $ \underset{-3}{\mathop{NH_3}},<\underset{+5}{\mathop{N_2O_5}},<\underset{+2}{\mathop{NO}},<\underset{0}{\mathop{N_2}}, $ (incorrect) [b] $ \underset{+5}{\mathop{N{{O}^{+}}_2}},<\underset{+5}{\mathop{N{{O}^{-}}_3}},<\underset{+3}{\mathop{N{{O}^{-}}_2}},<\underset{-1/3}{\mathop{{{N}^{-}}_3}}, $ (incorrect) [c] $ \underset{-3}{\mathop{N{{H}^{+}}_4}},<\underset{-2}{\mathop{N_2H_4}},<\underset{-1}{\mathop{NH_2OH}},<\underset{+1}{\mathop{N_2O}}, $ (incorrect) [d] $ \underset{+6}{\mathop{NO_3}},<\underset{-1/3}{\mathop{NaN_3}},<\underset{-3}{\mathop{NH_4^{+}}},<\underset{+1}{\mathop{N_2O}}, $ (incorrect)
