Redox Reactions And Electrochemistry Ques 320
Question: Charge required to liberate 11.5 g sodium is [AIIMS 1992; DCE 2002]
Options:
A) 0.5 F
B) 0.1 F
C) 1.5 F
D) 96500 coulombs
Show Answer
Answer:
Correct Answer: A
Solution:
$ N{a^{+}}+{e^{-}}\to Na $ Charge (in F) = moles of e- used = moles of Na deposited $ =\frac{11.5}{23}\ gm=0.5 $ Faraday.
