Redox Reactions And Electrochemistry Ques 319
Question: When 1F of electricity is passed through acidulated water, $ O_2 $ evolved is [MHCET 2004]
Options:
A) $ 11.2\ dm^{3} $
B) $ 5.6,dm^{3} $
C) $ 22.4\ dm^{3} $
D) $ 1.0\ dm^{3} $
Show Answer
Answer:
Correct Answer: B
Solution:
Reaction for electrolysis of water is $ 2H_2O $ ⇌ $ 4{H^{+}}+2{O^{2-}} $ $ 2{O^{2-}}\to O_2+4{e^{-}} $ $ 4{e^{-}}+4{H^{+}}\to 2H_2 $ $ \because $ $ n=4 $ so 4 Faraday charge will liberate 1 mole $ =22.4\ dm^{3} $ oxygen
$ \therefore $ 1 Faraday charge will liberate $ \frac{22.4}{4}=5.6\ dm^{3}\ O_2 $ .
